Question

What volume will 2.0 moles of nitrogen occupy at 0.947 atm and 20.0 °C?

Answer 1

V = 50.77 L

Step-by-step explanation:

Given that,

No. of moles, n = 2

Pressure, P = 0.947 atm

Temperature, T = 20°C = 293 K

We need to find the volume occupies by Nitrogen gas. Using gas law,

`PV=nRT\\\\V=(nRT)/(P)`

Where

R is gas constant

Put all the values,

`V=(2* 0.08205* 293)/(0.947)\\\\V=50.77\ L`

So, the volume occupied by the gas is equal to 50.77 L.