Question

A car was running in the velocity of 72km/h. What will be its velocity after 5s if it's acceleration is -2m/s^2 ?​

Answer 1

To determine the car's velocity after 5 seconds, we can use the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Given that the initial velocity of the car is 72 km/h, we convert it to m/s and substitute the values into the equation to find the velocity of the car after 5 seconds is 10 m/s.

Step-by-step explanation:

To determine the velocity of the car after 5 seconds, we can use the equation:

v = u + at

Where:

• v is the final velocity
• u is the initial velocity
• a is the acceleration
• t is the time

Given that the initial velocity of the car is 72 km/h, we need to convert it to m/s first:

u = 72 km/h = 20 m/s

Substituting the values into the equation:

v = 20 m/s + (-2 m/s^2)(5 s)

Simplifying the equation:

v = 20 m/s - 10 m/s = 10 m/s

Therefore, the velocity of the car after 5 seconds will be 10 m/s.

Answer 2

10m/s

Step-by-step explanation:

a = v- u/ t

=> v = at + u

= -2 × 5 + 20

= 10m/ s. ( 72 km/ h = 20 m/ s)