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Please help me I’m stuck

Please help me I’m stuck-example-1
User Victorwoo
by
7.7k points

2 Answers

2 votes

Answer:

Explanation:

use Pythagoras's theorem to find the hypontenuse of the isosceles triangle on the right side.

hyp = sqrt [ 5^2 + 5^2 ]

hyp = sqrt [ 50 ]

hyp = 7.0710678

now we know the adjacent side of the triangle on the left , since it's the same as the hypotenuse of the triangle on the right.

SOH CAH TOA ( to remember how the trig funct. fit on triangles)

CAH Cos(Ф) = adj / hyp

cos(Ф) = 7.0710678 / 8

Ф = arcCos( 7.0710678 / 8 )

Ф = 27.8855668°

TOA Tan(Ф) = x / 7.0710678

Tan( 27.8855668° ) = x / 7.0710678

7.0710678 * Tan( 27.8855668° ) = x

3.741657 = x

x = 3.7 ( to the nearest 10th )

User Taylor Hughes
by
8.8k points
5 votes

Answer:


x = 3.7

Explanation:

We can find the side of the hypotenuse by applying pythagorean theorem.


{5}^(2) + {5}^(2) = {x}^(2)


25 + 25 = {x}^(2)


50 = {x}^(2)


x = 5 √(2)

Now we can apply pythagorean theorem on the other triangle


(5 √(2) ) {}^(2) + {x}^(2) = {8}^(2)


50 + {x}^(2) = 64


{x}^(2) = 14


x = √(14)


x = 3.7

User Waleed Iqbal
by
8.5k points

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