Question

Find the distance of line segment AB between the points at (8,0) and (5,9)

Answer 1

Approximately 3.605 units

Explanation:

AB= B -A =
`\left[\begin{array}{ccc}5\\9\end{array}\right]` -
`\left[\begin{array}{ccc}8\\0\end{array}\right]` =
`\left[\begin{array}{ccc}-3\\9\end{array}\right]`

|AB| = √x²+y² = √(-3)²+2² = √9+4 =√13 = 3.605 units