Question

Please help giving a lot of points- A rollercoaster cart that has a mass of 4500 kg has 67.5 kJ (kilojoules), or 67,500 J (joules), of gravitational potential

energy. What is its height above the ground?


PT.2


The same 4500 kg rollercoaster cart is moving with 63.0 kJ (kilojoules), or 63,000 J (joules), of kinetic energy at the


bottom of its biggest hill. What is its velocity?

Answer 1

(a) h = 1.5 m (b) v = 5.29 m/s

Step-by-step explanation:

1. Given that,

Mass of a rollercoaster cart, m = 4500 kg

It has 67,500 J of gravitational potential energy.

We know that, the gravitational potential energy is given by :

`E=mgh`

Put all the values,

`h=(E)/(mg)\\\\h=(67500)/(4500* 10)\\\\h=1.5\ m`

2. The kinetic energy of an object is given by :

`E=(1)/(2)mv^2\\\\v=\sqrt{(2E)/(m)}\\\\v=\sqrt{(2* 63000)/(4500)}\\\\v=5.29\ m/s`

Hence, this is the required solution.