Question

PLZ HELP!!! I'm begging you! Problem: If each letter of the alphabet is worth two more numbers than the number before it (1=1, 2=3), what is the entire alphabet worth?

Answer 1

676

Explanation:

A = 1

B = 3

C = 5

D = 7

...

Z = 51

1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23 + 25

(+) + 51 + 49 + 47 + 45 + 43 + 41 + 39 + 37 + 35 + 33 + 31 + 29 + 27

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52 + 52 + 52 + 52 + 52 + 52 + 52 + 52 + 52 + 52 + 52 + 52 + 52

13 * 52 = 676

Answer: 676

Answer 2

676

Explanation:

I think this is an arithmetic series, so

Sn = 26/2[2(1) + (26 - 1)2]

Sn = 13[2 + 50]

Sn = 13[52]

Sn = 676