Question

Answer all questions 9-13!!!!​

Answer 1

9) 3.7 in

10) 12 in²

11) 18 in³

12) V=432π cm³

TSA= 216π cm²

13)V=448π ft³

TSA=240π ft²

Answer 2

9) 3.7 in

10) 12 in²

11) 18 in³

12) V=432π cm³

TSA= 216π cm²

13)V=448π ft³

TSA=240π ft²

Explanation:

9) Since all side of the trapezium are the same the height = perpendicular line which is 3.7 in

10) 3×4 (the quadrilateral at the bottom)

11)∵ A= Cross-sectional area× height

⇒A= Area of the trapezium × 4

∴ A=
`(1)/(2) \\` (sum of the parallel sides) × 4

A=
`(1)/(2) \\` (3+6) × 4

A= 18 in²

12) V=πr²h

V=π(6)²(12)

⇒V=432 cm³

TSA=2(πr²)+2πrh

TSA=2(π(6)²)+2π(6)(12)

⇒TSA=240π cm²

13. V=πr²h

V=π(8)²(7)

V=448π ft³

TSA=2(πr²)+2πrh

TSA=2(π(8)²)+2π(8)(7)

TSA=240π ft²