Question

Write your question here (Keep it simple and clear to get the best answer) If jun has 12 T-shirt 6 pairs of parts, and 3 pairs of share, how many possibilities can be'drace himself up for the day?

Answer 1

the number of possibilities that can be drace himself up for the day is 216

Explanation:

Given that

jun has 12 t-shirts,6 pairs of pants and 3 pairs of shoes

We need to find out the possibilities that can be drace himself up for the day

So here

`= 12C_1 * 6C_1 * 3C_1\\\\= (12!)/(1!(12 - 1)!) * (6!)/(1!(6 - 1)!) * (3!)/(1!(3 - 1)!)\\\\= (12!)/(1!(11)!) * (6!)/(1!(5)!) * (3!)/(1!(2)!)\\\\= 12 * 6 * 3\\\\= 216`

Hence, the number of possibilities that can be drace himself up for the day is 216

The same would be considered and relevant too