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What is the equation of a line that goes through (2,5) and (-2, 3)?​

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Answer:

y = 1/2x+4

Explanation:

First find the slope

m= (y2-y1)/(x2-x1)

= (3 - 5)/(-2 -2)

= -2/-4

= 1/2

Using point slope form

y -y1 = m(x-x1) where m is the slope and (x1,y1) is a point on the line

y-5 = 1/2(x-2)

Distribute

y-5 = 1/2x -1

Add 5 to each side

y-5+5 = 1/2x -1+5

y = 1/2x+4

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