Complete the square to go to the conic form of the circle. x^{2}+y^{2}+8x-2y+1=0

asked Sep 8, 2022 230k views

5 votes

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6 votes

Answer:

Explanation:

$x^2+8x+y^2-2y=-1\\\\x^2+8x+16+y^2-2y+1=-1+16+1\\(x+4)^2+(y-1)^2=16\\\\(x+4)^2+(y-1)^2 = 4^2$

Alicea answered Sep 15, 2022

7.6k points

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