9514 1404 393
Answer:
x ∈ {-1/2, 1, 2-√3, 2+√3}
Explanation:
The given zeros mean that one of the quadratic factors of the given polynomial is ...
(x -2)^ -3 = x^2 -4x +1
When that is factored out (see first attachment), the remaining quadratic is ...
2x^2 -x -1
This can be factored as ...
= (2x +1)(x -1)
which has roots that make these factors zero: x = -1/2, x = 1.
So, all of the zeros of the given polynomial are ...
-1/2, 1, 2-√3, 2+√3 . . . all zeros
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A graphing calculator can often point to the zeros of the function quite nicely.
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Additional comments
When p is a zero of a polynomial, (x-p) is a factor of it. The given zeros mean that factors are (x-2-√3) and (x-2+√3). The product of these factors is the difference of the squares (x-2)^2 and (√3)^2, so is (x -2)^2 -3.
Using the pattern for the square of a binomial, we see this is ...
(x-2)^2 = x^2 -2·2x +2^2 = x^2 -4x +4
The product of the given factor is then 3 subtracted from this square. The given zeros mean there is a quadratic factor of ...
(x-2-√3)(x-2+√3) = (x-2)^2 -3 = x^2 -4x +4 -3 = x^2 -4x +1