83.4k views
1 vote
Suppose {an) is an arithmetic sequence with a16=12 and a7=30. Find a9.

User MattMatt
by
6.7k points

1 Answer

2 votes

Answer:

a9 = 26

Explanation:

nth term of an arithmetic sequence an = a + (n-1)d

a16 = a+15d = 12.... 1

a7 = a+6d = 30.....2

Subtract

15d - 6d = 12 - 30

9d = -18

d =-18/9

d = -2

Substitute d = -2 into 1

a + 15d = 12

a+15(-2) = 12

a - 30 = 12

a = 12 + 30

a = 42

Get a9;

a9 = a+8d

a9 = 42+8(-2)

a9 = 42 - 16

a9 = 26

hence the 9th term of the sequence is 26

User HienPham
by
6.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.