Find the zero of the function f(x)=0.8e^2x -9. Round to the nearest hundredth.

Question

asked Jun 28, 2022 97.3k views

1 Answer

Mups · Answer 1 · 2022-07-02T15:44:53+0000

Answer: x=1.21

Explanation:

Given

Function is
f(x)=0.8e^(2x)-9

To find the zeroes, equate the function equal to zero

$\Rightarrow 0.8e^(2x)-9=0\\\\\Rightarrow e^(2x)=(9)/(0.8)\\\Rightarrow e^(2x)=11.25$

taking natural logarithm both sides

$\Rightarrow \ln (e^(2x))=\ln (11.25)\\\Rightarrow 2x=2.42\\\Rightarrow x=1.21$

The zero of the equation is 1.21