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Find the surface area of the composite solid. 6 ft 4 ft 1 5 ft 5 ft​

Find the surface area of the composite solid. 6 ft 4 ft 1 5 ft 5 ft​-example-1
User Nweiler
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2 Answers

4 votes

Sa Of Rectangular Prism - 65

Sa Of Pyramid - 85

TOTAL SURFACE AREA - 150

User Rick Jolly
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5.8k points
4 votes

The surface area of the composite solid is approximately 128.56 square feet.

Triangular prism:

Area of the base (triangle): 1/2 * base * height = 1/2 * 5 ft * 4 ft = 10 ft²

Area of each of the other faces (rectangles): height * width = 6 ft * 5 ft = 30 ft²

Since there are two of these rectangles, the total area of the rectangles is 2 * 30 ft² = 60 ft²

Adding the area of the base and the rectangles, the total surface area of the triangular prism is 10 ft² + 60 ft² = 70 ft²

Pyramid:

Area of each of the triangles: 1/2 * base * height

We need to find the heights of the triangles. We can use the Pythagorean theorem to do this.

In a right triangle where the hypotenuse is 6 ft and one leg is 5 ft, the other leg (the height of the triangle) is √(6² - 5²) = √11 ft.

Therefore, the area of each triangle is 1/2 * 5 ft * √11 ft ≈ 14.64 ft²

Since there are four triangles on the pyramid, the total area of the triangles is 4 * 14.64 ft² ≈ 58.56 ft²

Total surface area:

Adding the surface area of the triangular prism and the pyramid, the total surface area of the composite solid is 70 ft² + 58.56 ft² ≈ 128.56 ft²

User GalacticCowboy
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