Question

If I had 3.50 x 10 24molecules of Cl2 gas, how many grams is this?

Answer 1

412 g Cl₂

General Formulas and Concepts:

Atomic Structure

• Reading a Periodic Table
• Moles
• Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

• Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

[Given] 3.50 × 10²⁴ molecules Cl₂

[Solve] grams Cl₂

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of Cl₂ - 2(35.45) = 70.9 g/mol

Step 3: Convert

1. [DA] Set up:
   `\displaystyle 3.50 \cdot 10^(24) \ molecules \ Cl_2((1 \ mol \ Cl_2)/(6.022 \cdot 10^(23) \ molecules \ Cl_2))((70.9 \ g \ Cl_2)/(1 \ mol \ Cl_2))`
2. [DA] Divide/Multiply [Cancel out units]:
   `\displaystyle 412.072 \ g \ Cl_2`

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

412.072 g Cl₂ ≈ 412 g Cl₂