Question

What volume will 28 grams of nitrogen gas occupy at 27 Celsius and a
pressure of 785 mm Hg?

Answer 1

Answer:
`2.49\ m^3`

Step-by-step explanation:

Given

Mass of nitrogen present
`m=28\ g`

Temperature
`T=27^(\circ)C\equiv 300\ K`

Pressure
`P=785\ mm\ \text{of}\ Hg\ \text{or}\ 1.032\ atm`

The molar mass of Nitrogen
`M=28\ g/mol`

No of moles of nitrogen present

`n=(m)/(M)\\\\n=(28)/(28)\\\\n=1`

Using
`PV=nRT`

`\Rightarrow 1.032* V=1* 8.314* 300\\\\\Rightarrow V=(2494.2)/(1.032)\\\\\Rightarrow V=2494.2\ L\ \text{or}\ 2.49\ m^3`