Answer:
T₂ = 1.2 s
Explanation:
The time period of a simple pendulum is given by :
![T=2\pi \sqrt{(L)/(g)}](https://img.qammunity.org/2022/formulas/mathematics/college/xr7tkwi05eniufyfjp4zy63qn274etyktf.png)
Where
L is length of the pendulum
g is acceleration due to gravity
We have,
T₁ = 1.4 s, L₁ = 0.49 m, L₂ = 0.36 m, T₂= ?
![(T_1)/(T_2)=\sqrt{(L_1)/(L_2)} \\\\T_2=\frac{T_1}{\sqrt{(L_1)/(L_2)}}\\\\T_2=\frac{1.4}{\sqrt{(0.49)/(0.36)}}\\\\T_2=1.2\ s](https://img.qammunity.org/2022/formulas/mathematics/college/ktwqo957lufe9diy9oe850bkkab82gt9ce.png)
So, the new time period is equal to 1.2 seconds.