Question

Limestone has a density of 2.72 g/cm3. What is the mass of 8.92 cm3 of limestone?

Answer 1

it should be 24.2624 because if there’s 2.72g in every cm3 and there are 8.92 cm3, then you simply multiply the two numbers
hope this helped :)

Answer 2

`\boxed {\boxed {\sf 24.2624 \ g}}}`

Step-by-step explanation:

Density measures mass per volume. The volume is

`\rho=(m)/(v)`

The density of limestone is 2.72 grams per cubic centimeter. We have a piece of limestone with a volume of 8.92 cubic centimeters.

• ρ= 2.72 g/cm³
• v= 8.92 cm₃

Substitute the values into the formula.

`2.72 \ g/cm^3=(m)/(8.92 \ cm^3)`

Now we solve for m, the mass, by isolating the variable.

m is being divided by 8.92 cubic centimeters. The inverse of division is multiplication, so we multiply both sides by 8.92 cubic centimeters.

`8.92 \ cm^3 * 2.72 \ g/cm^3=(m)/(8.92 \ cm^3)* 8.92 \ cm^2`

`8.92 \ cm^3 * 2.72 \ g/cm^3=m`

The units of cubic centimeters cancel out.

`24.2624 \ g =m`

The mass of this piece of limestone is 24.2624 grams.