Question

A 3mL sample of a 200 Molar solution is left open on a lab

counter for two weeks, after which the concentration of the solution is 6 M. What is the new volume of the solution?

Answer 1

Answer: New volume of the solution is 100 mL.

Step-by-step explanation:

Given:
`V_(1)` = 3 mL,
`M_(1)` = 200 M

`M_(2)` = 6 M,
`V_2` = ?

Formula used to calculate the new volume of solution is as follows.

`M_(1)V_(1) = M_(2)V_(2)`

Substitute the values into above formula as follows.

`M_(1)V_(1) = M_(2)V_(2)\\200 M * 3 mL = 6 M * V_(2)\\V_(2) = (200 M * 3 mL)/(6 M)\\= 100 mL`

Thus, we can conclude that new volume of the solution is 100 mL.