Given:
Either has a school certificate or diploma or even both = 20 people
Having school certificates = 14
Having diplomas = 11
To find:
The number of people who have a school certificate only.
Solution:
Let A be the set of people who have school certificates and B be the set of people who have diplomas.
According to the given information, we have
![n(A)=14](https://img.qammunity.org/2022/formulas/mathematics/high-school/7x7lrfcrrife5g8by9x372q24rmn4uv6t4.png)
![n(B)=11](https://img.qammunity.org/2022/formulas/mathematics/high-school/v2uqextj1r8voam7q8y20txwdpow8ozzyn.png)
![n(A\cup B)=20](https://img.qammunity.org/2022/formulas/mathematics/high-school/hhbejcztfi53y75ox2qelcppnwftp51vuj.png)
We know that,
![n(A\cup B)=n(A)+n(B)-n(A\cap B)](https://img.qammunity.org/2022/formulas/mathematics/high-school/opwv182tu4q75jd4xrv4g25slevdyhr2yy.png)
![20=14+11-n(A\cap B)](https://img.qammunity.org/2022/formulas/mathematics/high-school/mejlpblj1ouk5omi96kmnsmdg00s2h3lo1.png)
![20=25-n(A\cap B)](https://img.qammunity.org/2022/formulas/mathematics/high-school/l97ijfncqfd3fn19hayv8ixch89rrsv3wg.png)
Subtract both sides by 25.
![20-25=-n(A\cap B)](https://img.qammunity.org/2022/formulas/mathematics/high-school/qz8lpd0isvvs85ra88vswrnnr3i2zxaxgd.png)
![-5=-n(A\cap B)](https://img.qammunity.org/2022/formulas/mathematics/high-school/k8ub3gdtfhqb87vgw3s16fuwtiew2howsf.png)
![5=n(A\cap B)](https://img.qammunity.org/2022/formulas/mathematics/high-school/q6sl4r0wyd5qp1sa51cjjyzs36xc4h8f07.png)
We need to find the number of people who have a school certificate only, i.e.
.
![n(A\cap B')=n(A)-n(A\cap B)](https://img.qammunity.org/2022/formulas/mathematics/high-school/kppt5dpbsgabfqvu66bvzphv2m6kl5m306.png)
![n(A\cap B')=14-5](https://img.qammunity.org/2022/formulas/mathematics/high-school/64sq9997x3u7mxbbig2sw9l6e7ep1kxfip.png)
![n(A\cap B')=9](https://img.qammunity.org/2022/formulas/mathematics/high-school/nrumcwhmgux7mukhyr27hqcgqpntl2d01e.png)
Therefore, 9 people have a school certificate only.