Question

Sheila is twice as old as Rita. In two years, Sheila will be four times as old as Rita was nine years ago. How old is each now?

Answer 1

Answer: (Sorry for not wording it correctly I had to reword it)

Step-by-step explanation: Let R be the current age of Rita. Let S be the current age of her son.

Rita is twice as old as her son.

=> R = 2S

In 4 years, R will be 4 times as old as S was 9 years ago

=> R + 4 = 4 (S - 9)

Solve for R, and S:

=> R + 4 = 4 (S - 9)

=> (2S) + 4 = 4(S - 9)

=> 2S + 4 = 4S - 36

=> 2S - 4S = -36 - 4

=> -2S = -40

=> S = 20

Find R:

=> R = 2S

=> R = 2(20)

=> R = 40

Therefore, Rita is 40, her son is 20.