Question

Find the factors of x3−7x−6

(x+3)(x+2)(x−1)
(x−3)(x+2)(x+1)
(x−4)(x−2)(x+1)
(x−6)(x−1)(x+1)

Answer 1

• B. (x−3)(x+2)(x+1)

Explanation:

Possible options are 1 or 2 as each has odd number of negative coefficients.

Open parenthesis and verify:

• (x+3)(x+2)(x−1) = ³ + 4x² + x - 6, false
• (x−3)(x+2)(x+1) = x³ - 7x - 6, true