Answer:
length = 18yd
Width = 10yd
Explanation:
Complete question
A rectangular parking lot has a length that is 8 yards greater than the width. The area of the parking lot is 180 square yards. Find the length and the width.
Area of the parking lot - length * width
A = LW
Given
Area = 180sq. yd
If the parking lot has a length that is 8 yards greater than the width, then;
L = 8 + W
The area becomes;
A = (8+W)W
180 = 8W+W²
W²+8W - 180 = 0
W²+18W-10W - 180 = 0
W(W+18)-10(W+18) = 0
(W-10)(W+18) = 0
W-10 = 0
W = 10yd
Since L = 8 + W
L = 8 + 10
L = 18yd
Hence the length and the width area 18yd and 10yd respectively