Question

Find the 8th term of the geometric sequence show below

Answer 1

Alli khanaw .................

Answer 2

8x^36

Explanation:

first term (a) =
`8x^(8)`

Second term (t2)=
`8x^(12)`

common ratio (r)

=
`(8x^(12) )/(8x^(8) )`

=
`x^(4)`

now the 8th term of the G.S is

t8 =
`ar^(n-1)`

=
`8x^8 * (x^4)^8^-^1`

=
`8x^8 * (x^4)^7\\`

=
`8x^8 *x^2^8\\= 8x^3^6`

hope it will help