Question

How many kilojoules of heat must be transferred to a 480-g aluminum pizza pan to raise its temperature from 22°C to 234°C? The specific heat of aluminum in this temperature range is 0.96 J/g.°С. Show your work.​

Answer 1

Step-by-step explanation:

the answer and the working out is shown above.

Answer 2

97.7 kJ

Step-by-step explanation:

We'll use the formula for specifc heat: Q=mcΔT

Q= heat/energy (Joules), m= mass (grams), c= specific heat (different for each substance and is usually given)

ΔT= final temperature - initial temperature

Let's check our given units and see if they're the correct, here they all are. Let's plug in what we know.

Q=mcΔT

Q=(480)(0.96)(234 - 22)

Q=(480)(0.96)(212)

Q= 97,690 J

Before we submit an answer, let's check out units. We have our answer in Joules, but we want it it kilojoules, so we'll convert it knowing that:

1000 Joules = 1 kilojoule

97,690J x
`(1 kJ)/(1000J)` = 97.7kJ