Given:
PQRS is a rectangle.
![PS=5\ cm,\ PR=13\ cm](https://img.qammunity.org/2022/formulas/mathematics/high-school/6ghcylawmbhpbpec7dj6r3az3dmlf29p7c.png)
To find:
The length of SR and QS.
Solution:
We know that, all interior angles of a rectangle are right angle. So,
.
According to the Pythagoras theorem, in a right angle triangle,
![Hypotenuse^2=Base^2+Perpendicular^2](https://img.qammunity.org/2022/formulas/mathematics/high-school/7t36b8r09zt78n0wnyh0xx7hiol93gqv7q.png)
Using Pythagoras theorem in triangle PRS, we get
![PR^2=PS^2+SR^2](https://img.qammunity.org/2022/formulas/mathematics/high-school/4jwynqqns17rwinga1gwrvi1u3amvdcbss.png)
![13^2=5^2+SR^2](https://img.qammunity.org/2022/formulas/mathematics/high-school/vppjtf9ey3de28dse3uu266g0nppfspeo7.png)
![169-25=SR^2](https://img.qammunity.org/2022/formulas/mathematics/high-school/nm26cpraf2vrtstb9jutnwctx0nmgxakl9.png)
![144=SR^2](https://img.qammunity.org/2022/formulas/mathematics/high-school/sldc0qt9lamuvhaobttv2ud90rxujtq9z6.png)
Taking square root on both sides.
![√(144)=SR](https://img.qammunity.org/2022/formulas/mathematics/high-school/l0ezz1ox5mi7ludj599pj1f6gk3pd01q3s.png)
![12=SR](https://img.qammunity.org/2022/formulas/mathematics/high-school/fyzkkz5thur9e1sczrl5fupj6v3mtvstsy.png)
So, the measure of SR is 12 cm.
We know that the diagonals of a rectangle are equal. PR and QS are the diagonals of the rectangle PQRS. So,
![PR=QS](https://img.qammunity.org/2022/formulas/mathematics/high-school/jcssp30smqdr3zoqadi2t3yrdbupmj9k1z.png)
![13=QS](https://img.qammunity.org/2022/formulas/mathematics/high-school/tthv446yqyzewm2qyx0hco533udqsod09j.png)
Therefore, the length of SR is 12 cm and the length of QS is 13 cm.