Question

Three moles of oxygen gas is stored in a 2.5-liter container at 35°C. What is the pressure of this gas?

Answer 1

30.34 atm

Step-by-step explanation:

Using the general gas law formula;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

T = temperature (K)

R = gas law constant (0.0821 Latm/molK)

According to the information provided in this question,

n = 3mol

T = 35°C = 35 + 273 = 308K

V = 2.5L

P = ?

Using PV = nRT

P = nRT/V

P = 3 × 0.0821 × 308/2.5

P = 75.8604 ÷ 2.5

P = 30.34 atm.