Question

How do I solve this?

Answer 1

The heat contained is 1236 Joules

Step-by-step explanation:

As we know

`Q = mc\Delta`T

Where

`\Delta`T is the change in temperature

m is the mass in grams

c is the specific heat of water (ice) = 2.06 joules/gram

Substituting the given values, we get -

`Q = 20 * (-15+45)*2.06\\Q = 20*2.06*30\\Q = 1236`Joules