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In the field of com, yellow kernel color is governed by a dominant allele: white, by the recessive allele. A

random sample of 1,000 kernels from a population that is in a Hardy Weinberg equilibrium reveals that 910 are
yellow and 90 are white
a Wha is the frequency of the white allele in the population?
D. What is the frequency of the yellow allele in the population?
c. What percent of the population is heterozygous?

User Kishori
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1 Answer

2 votes

Answer:

The correct answer is -

a. 0.3

b. 0.7

c. 42

Step-by-step explanation:

Given:

yellow kernel = 910

white kernel = 90 which means = 9 percent recessive alleles

Solution Hardy-Weinberg equations first.

p+q=1 and p^2+2pq+q^2=1

With "p" being the dominant allele and "q" being the recessive allele

We know that 9% shows the recessive trait. This means that the fraction of the population with the recessive trait,

q^2 = 0.9

Then q = 3,

p will be - 1-0.3 = 0.7

then 2pq = 2*7*3 = 42 % will be heterozyhous

User Rns
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