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What is the vertex of f(x)=x^2-9x+14

User Jseb
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1 Answer

5 votes

Its going to be a lot of steps

Step one

To complete the square, the same value needs to be added to both sides

f(x)+?=x^2 -9x+?+14

Step two

To complete the square add to the expression

x^2 -9 + 81/4= ( x- 9/2 ) ^2 add 81/4
To the expression


f(x)+?=x^2 -9+ 81/4 + 14

Step three

Since 81/4 was added to the right-hand side, also add 81/4 to the left-hand side

f(x)+81/4=x^2 -9x+81/4+14

Step four

Use a^2-2ab +b^2 = ( a-b)^2 to factor the expression

f(x)+81/4=(x-9/2)^2+14

Step five

Move the constant to the right-hand side and change its sign

f(x)=(x-9/2)^2 + 14- 81/4

Last step

Calculate the difference

F(x)=(x-9/2)^2 -25/4


That was to long
Karl:D

What is the vertex of f(x)=x^2-9x+14-example-1
User Fidi
by
5.8k points