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1 vote
HELP PLEASE JJFFNFNFNF

HELP PLEASE JJFFNFNFNF-example-1

2 Answers

4 votes

Answer:

B

Explanation:

Option B is correct because from the data it's visible that all the data are around 6 miles in other words clustered. In Class A half of them are on left and half are on right. Option A is wrong because there are 17 students in class A and 18 students in class B.

Option C is wrong because the mean is 8.2 and the median is 6.

To find mean add up all the miles the students chose and divide by total students (4+4+4+4+4+5+5+5+6+6+12+13+13+13+13+14+14)/17 = 8.2

To find the median line up all the numbers and find the one in middle. It's 6.

Option D is wrong because the range for class A is (14-4)=10

and class B is (9-3)=6. So the range of class A is greater than class B.

To find range maximum value-minimum value

User Myworld
by
5.0k points
3 votes

Answer:

A.

  • 17 vs 18, not true

B.

  • True

C.

Mean:

  • (4*5 + 5*3 + 6*2 + 12 + 13*4 + 14*2)/17 = 8.17

Median:

  • 6

Mean ≠ median, not true

D.

  • 14 - 4 = 10
  • 9 - 3 = 6,
  • 10 > 6, not true
User Samik
by
5.2k points