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A bag has 2 mint cookies, 1 donut, and 4 wafer cookies. Two items are drawn one at a time without replacement. What is the probability of first drawing 1 donut, and next drawing 1 mint cookie?

User Paweldac
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1 Answer

4 votes

Answer: 1/21

Explanation:

total = 2 + 1 +4 = 7

1/7 x 2/(7-1) = 2/42

2/42 simplifies to 1/21

1/7: 1 doughnut out of a total of 7 items

2/(7-1): 2 mint cookies are available in the pool out of 6 items -> since one item has already been chosen without replacement, so now the total is 6.

User Jose B
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