Question

Find the zeros of the quadratic equation-
v(5v-7)=0

Answer 1

Explanation:

v(5v-7)=0

We multiply parentheses

5v^2-7v=0

a = 5; b = -7; c = 0;

Δ = b2-4ac

Δ = -72-4·5·0

Δ = 49

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

v1 = −b−√Δ/2a

v2 = -b+√Δ/2a

√Δ = √49 = 7

v1 = -(−7)−7/2*5 = 0/10 = 0

v2 = -(−7)+7/2*5 = 14/10 = 1+2/5

Answer 2

`\huge\text{Hey there!}`

`\huge\textbf{We start off with this current equation:}`

`\mathbf{v(5v - 7) = 0}`

`\huge\textbf{Solving for the answer to your question:}`

`\mathbf{v(5v - 7) = 0}`

`\huge\textbf{Convert your current equation to:}`

`\mathbf{1v(5v - 7) = 0}`

`\huge\textbf{Distribute v or 1 within the parentheses:}`

`\mathbf{\rightarrow 1v(5v) + 1v(-7) = 0}`

`\mathbf{\rightarrow 5v^2 - 7v = 0}`

`\huge\textbf{Factor the left side of the equation:}`

`\mathbf{v(5v - 7) = 0}`

`\huge\textbf{Fator each of the sides to equal to 0:}`

`\mathbf{v = 0\ OR\ as\ in\ 5v - 7 = 0 }`

`\huge\textbf{Simplify the current equation above:}`

`\mathbf{v = 0\ or\ v = (7)/(5)}`

`\huge\textbf{Thus, the answer should most likely be:}`

`\huge\boxed{\mathsf{v = 0\ or\ v = (7)/(5)}}\huge\checkmark`

~
`\frak{Amphitrite1040:)}`