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Write the equation of the line that passes through the points (−3, 5) and (2, -10) in slope-intercept form.​

User Jrushing
by
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1 Answer

4 votes

Answer:


y=-3x-4

Explanation:

Hi there!

Slope intercept form:
y=mx+b where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)

1) Determine the slope (m)


m=(y_2-y_1)/(x_2-x_1) where the two given points are
(x_1,y_1) and
(x_2,y_2)

Plug in the given points (−3, 5) and (2, -10)


m=(-10-5)/(2-(-3))\\m=(-10-5)/(2+3)\\m=(-15)/(5)\\m=-3

Therefore, the slope is -3. Plug -3 into
y=mx+b as m:


y=-3x+b

2) Determine the y-intercept (b)


y=-3x+b

Plug one of the given points, (−3, 5) or (2, -10) into the equation and isolate b


5=-3(-3)+b\\5=9+b

Subtract 9 from both sides


5-9=9+b-9\\-4=b

Therefore, the y-intercept is -4. Plug -4 into
y=-3x+b as b:


y=-3x-4

I hope this helps!

User Robin Burchell
by
8.2k points

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