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How many mL of 3.0 M HCl are needed to make 300.0 mL of 0.10 M HCl?

User MazzMan
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1 Answer

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Answer:

V₁ = 10 mL

Step-by-step explanation:

M₁V₁ = M₂V₂

M₁ = Initial molarity

V₁ = Initial volume of HCl

M₂ =Final molarity

V₂ = Final volume

Now we will put the values.

3.0 M ×V₁ = 0.10 M×300.0 mL

3.0 M ×V₁ = 30 M.mL

V₁ = 30 M.mL /3.0 M

V₁ = 10 mL

hope its helpp

User Jason FB
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