Question

A gas has the volume of 45mL at 25 C is heated to 50 C. What is the new volume of the gas? P1V1 = P2V2 V1/T1 = V2/T2 PV = nRT V1/T1 x V2/T2​

Answer 1

Option b (V1/T1 = V2/T2) is the right alternative or the new volume will be "0.048 L".

Step-by-step explanation:

The given values are:

Temperature,

T₁ = 25°C

or,

= 298.15 K

T₂ = 50°C

or,

= 323.15 K

Volume,

V₁ = 45 mL

or,

= 0.045 L

V₂ = ?

As we know,

⇒
`(V_1)/(T_1) =(V_2)/(T_2)`

Or,

⇒
`V_2=(V_1* T_2)/(T_1)`

On substituting the values, we get

⇒
`=(0.045* 323.15)/(298.15)`

⇒
`=(14.541)/(298.15)`

⇒
`=0.048 \ L`