Question

How many calories of heat were added to 167.9 g of water to raise its temperature from 25oC to 55oC?

Answer 1

Q = 5036.9 calories

Step-by-step explanation:

Given that,

Mass, m = 167.9 g

The temperature raises from 25°C to 55°C.

The specific heat of water,c = 4.184 J/g °C

We need to find the heat added to water. We know that,

`Q=mc\Delta T\\\\=167.9 * 4.184* (55-25)\\\\=21074.8\ J`

or

Q = 5036.9 calories

So, 5036.9 calories of heat is added.