Question

Solve the quadratic equation using any method. Round to the nearest tenth if neccessary. Any Help Is Appreciated

Answer 1

`x = -0.8\ or\ x = 0.5`

Explanation:

Given [Missing from the question]

`6x^2 + 2x - 2.5 = 0`

Required

Solve

Using factorization, we have:

`6x^2 + 2x - 2.5 = 0`

Expand 2x

`6x^2 - 3x+5x - 2.5 = 0`

Factorize

`3x(2x - 1)+2.5(2x - 1) = 0`

Factor out 2x - 1

`(3x +2.5)(2x - 1) = 0`

Split:

`(3x +2.5) = 0\ or\ (2x - 1) = 0`

In both cases, solve for x

`3x = -2.5\ or\ 2x = 1`

`x = -(2.5)/(3)\ or\ x = (1)/(2)`

`x = -0.8\ or\ x = 0.5` --- approximated