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On a basketball court there is a semicircle above the free throw line that has a radius of 7 find the area of semicircle

1 Answer

3 votes

Answer:
77\ \text{sq. units}

Explanation:

Given

The radius of the semi-circle is
r=7

We know, area of the circle is
\pi r^2

So, the area of the semi-circle is half of it i.e.
(1)/(2)\pi r^2

Put the value


\Rightarrow (1)/(2)*\pi * 7^2=76.97\\\Rightarrow \approx 77\ \text{sq. units}

The area of the semi-circle is
77\ \text{sq. units}

User Dileep
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