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For the reaction of C 2H 4( g) with O 2( g), to form CO 2( g) and H 2O( g), what number of grams of CO 2 could be produced from 2.0 g of C 2H 4 and 5.0 g of O 2?

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Answer:

4.58g of CO₂ could be produced

Step-by-step explanation:

Based on the reaction:

C₂H₄(g) + 3O₂(g) → 2CO₂(g) + 2H₂O(g)

1 mole of C₂H₄ reacts with 3 moles of oxygen to produce 2 moles of CO₂

To solve this question we must find the moles of each reactant in order to find limiting reactant. With limiting reactant we can find the moles -And the mass- of CO₂ produced:

Moles C₂H₄ -Molar mass: 28.05g/mol-

2.0g * (1mol / 28.05g) = 0.0713moles

Moles O₂ -Molar mass: 32g/mol-

5.0g * (1mol / 32g) = 0.156moles

For a complete reaction of 0.0713 moles of C2H4 are required:

0.0713 moles C₂H₄ * (3 moles O₂ / 1 mol C₂H₄) = 0.214 moles of O₂

As there are just 0.156 moles, O₂ is limiting reactant.

The moles of CO₂ produced are:

0.156 moles O₂ * (2mol CO₂ / 3mol O₂) = 0.104 moles CO₂

The mass is -Molar mass CO₂: 44.01g/mol-

0.104 moles CO₂ * (44.01g / mol) =

4.58g of CO₂ could be produced

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