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3 votes
Shanice's school made $850 by selling 125 tickets to the annual talent show. They sold adult

tickets for $10 and student tickets cost $6. How many adult tickets did they sell? How many
student tickets did they sell?
Write a system of equations to represent this situation. Define your variables.

User Shanakay
by
4.9k points

2 Answers

4 votes

Answer:

25 adult tickets were sold and 100 student tickets were sold.

Explanation:

Let the number of adult tickets sold be x and the number of student tickets sold be y.

We know that the total amount collected from the tickets was $850, and that a total of 125 tickets were sold. We can use this information to come up with two equations.

10x + 6y = 850 - Equation 1

x + y = 125 - Equation 2

Then, use the substitution method to solve for either x or y first, followed by the other.

From equation two:

x + y = 125

x = 125 - y - Equation 3

Sub eqn 3 into eqn 1:

10(125-y) + 6y = 850

1250 - 10y + 6y = 850

1250 - 4y = 850

-4y = - 400

y - 100

Sub y = 100 into eqn 2:

x + 100 = 125

x = 25

Check:

10(25) + 6(100) = 850

User Oninea
by
5.1k points
5 votes
Let S = student
Let A = adult
First equation is total tickets
Second should be the cost
S + A = 125
6S + 10A = 850
Use substitution or elimination
S + A = 125
S = -A + 125
I used substitution
6(-A + 125) + 10A = 850
-6A + 750 + 10A = 850
4A + 750 = 850
4A = 100, A = 25 adult tickets
125 - 25 = 100

Solution: 100 student tickets
User David Momenso
by
4.3k points