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Find the vertex form of 4x^2+8x-8

1 Answer

3 votes

Answer:

4(x + 1)^2 - 12.

Explanation:

f(x) = 4x^2 + 8x - 8

f(x) = 4(x^2 + 2x) - 8

f(x) = 4[(x + 1)^2 - 1) - 8

f(x) = 4(x + 1)^2 - 4 - 8

f(x) = 4(x + 1)^2 - 12.

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