Answer:
6.7%
Explanation:
Mean = 32.7
Standard deviation = 1.8
Percentage of employees younger Than 30 years
Obtained the Standardized age, x < 30
Z = (x - mean) / standard deviation
Z = (30 - 32.7) / 1.8
Z = - 2.7 / 1.8
Z = - 1.5
Obtain the probability :
Using a Z probability calculator or standard normal table :
P(Z < - 1.5) = 0.066807
0.066807 * 100% = 6.7%