Question

You are replicating Gregor Mendel's famous experiment with sweet peas. The genotype for dominant smooth-seeded parent is designated AA, while the genotype for the wrinkled-seeded parent is aa. Using a punnet square predict the first generation for this cross. What are the genotypic and phenotypic ratios? SHOW ALL WORK.

Answer 1

The correct answer is -

A. genotype ration = 1/1 or 100% of Aa.

B. phenotype = all smooth-seeded.

Step-by-step explanation:

According to the question, in this experiment, the smooth seed is the dominant trait over the wrinkled seed. The wrinkled seed is recessive, therefore, represented by aa and dominant is represented by AA

gametes: A and A from smooth seeded parent and a and a from the wrinkled-seeded parent.

Punnett square:

A A

a Aa Aa

a Aa Aa

In this cross of F1 generation, all the offsprings are Aa in genotype 4/4 or 1/1 or 100 percent chances.

And phenotypically 100% chances of the smooth seed plants.