Question

What is the axis of symmetry for y=8x2+2x−6?

Answer 1

y=2( x -
`2^(2)`)-2

Explanation:

Use the vertex form, y=a(x -
`h^(2)`)+k to determine the values of A,H,K

a=2

h=2

k= -2

Since the value of a is positive the parabola opens up.

Find the vertex (h,k)

(2, -2)

Find p the distance from the vertex to the focus.

`(1)/(8)`

Find the focus

(2, -
`(15)/(8)`)

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

x=2