Answer:
6.0 (2 sig figs)
Step-by-step explanation:
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6.0cm
Given
focal length = 15.0cm
object distance = 10.0cm
Required
Image distance v
Using the formula
1/f = 1/u + 1/v
1/15 = 1/10+1/v
1/v = 1/15 + 1/10
1/v = 2+3/30
1/v = 5/30
v = 30/5
v = 6.0cm
Hence the image distance is 6.0cm
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