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What is the area of sector with a central angle of 160 and a diameter of 5.8 m? Round the answer to the nearest tenth.

A) 8.1 m^2

B) 4.0 m^2

C) 46.0 m^2

D) 11.7 m^2

User Cindia
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1 Answer

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Answer:


A=11.7\ m^2

Explanation:

Given that,

Central angle,
\theta=160^(\circ)

Diameter,d = 5.8 m

Radius, r = 2.9 m

We need to find the area of sector. The formula for the area of sector is given by :


A=(\theta)/(360)* \pi r^2\\\\=(160)/(360)* 3.14* 2.9^2\\\\=11.7\ m^2

So, the area of a sector is equal to
11.7\ m^2.

User Robert Gomez
by
7.6k points

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