Answer:
The solution of the system of equation is x = 3, and y = 24
Explanation:
The given system of equations are;
y = 8·x...(1)
y = 10·x -6...(2)
Solving the above system of linear equations using the comparison method, we first make one of the variables the subject of both equations
However, the given already have 'y' as subject, therefore, by comparison, we have;
y = y...(3)
8·x = 10·x - 6...(4)
From equation (4) given in the variable 'x', above, we have;
8·x = 10·x - 6
8·x - 8·x + 6 = 10·x - 6 + 6 - 8·x (the underlined items become zero)
∴ 6 = 10·x - 8·x = 2·x
6 = 2·x
∴ 2·x = 6
x = 6/2 = 3
x = 3
From equation (2), y = 8·x, we get;
y = 8·x
x = 3
∴ y = 8 × 3 = 24
y = 24
The values of 'x' and 'y' in the given system of equation is x = 3, y = 24.