What is the pH of a solution in which [OH-] = 1.0 x 10-2 M

asked Jun 21, 2022 71.0k views

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Answer:

Step-by-step explanation:

pOH = -log(1.0 x 10^-2) = 2

pH = 14 - pOH

pH = 14 - 2 = 12

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