Question

1 The prism-shaped roof has equilateral triangular bases. Use the model you created in question #1 to calculate the height of the roof, to the nearest tenth of a foot, if the side lengths each measure 25 feet. In your final answer, include all necessary calculations. You may include a sketch as part of your work.

2 To determine the amount of roofing materials needed, the area of the roof's entire surface is calculated, including the ceiling of the garage. Considering the sketch of the roofing design, create a formula to model the area of the roof's entire surface. In your final answer, include all of your calculations.

3The contractor in charge of the roofing project is trying to make the job the most cost effective for the homeowners. In order to cut back on the cost of supplies, he decides that a ceiling in the garage is not necessary. In other words, there will not be a barrier built between the garage and the roof. In two or more complete sentences, explain how these changes affect the model for the area of the roof's entire surface.

4The contractor in charge of the roofing project is trying to make the job the most cost effective for the homeowners. In order to cut back on the cost of supplies, he decides that a ceiling in the garage is not necessary. In other words, there will not be a barrier built between the garage and the roof. Create a formula modeling the area of the roof’s surfaces that the contractor will be purchasing supplies for.

5 Use the formula you created in the previous question to calculate the area of the roof that the contractor will be purchasing supplies for, assuming that the side length of the triangular bases is 25 feet and the length of each rectangular face is twice its width.

try your best i really need help!!

Answer 1

Explanation:

Step-by-step explanation: As shown in the attached figure, the prism-shaped roof has equilateral triangular bases, one of which is ΔABC. We need to create an equation that models the height of one of the roof's triangular bases in terms of its sides. Let ii be AD.

See the figure attached herewith, ΔABC forms an equilateral triangle, in which AD is the height. So, D will be the mid-point of BC and ∠ADB = ∠ADC = 90°.

Now, in ΔADB, we have

AD^2=AB^2-BD^2

AD^2=AB^2-(1/2AB^2)^2

AD=√3/4AB^2

we can find the height of any one of the roof's triangular bases.

2.1. Check picture 1. Let the one side of the triangle be a, drop one perpendicular, CD. Then triangle ADB is a right triangle, with hypothenuse a and one side equal to 1/2a. By the Pythagorean theorem, as shown in the picture, the height is √3/2a

2. if a=25 ft, then the height is √3/2a=√3/2*25=1.732/2*25=21.7(ft)

3. consider picture 2. Let the length of the roof be l feet.

one side of the prism (the roof) is a rectangle with dimensions a and l, so the area of one side is a*l

the lateral Area of the roof is 3a*l

the area of the equilateral surfaces is 2*(1/2*a*√3/2a)=√3/2a^2

so the total area of the roof is

4. The total area was the 2 triangular surfaces + the 3 equal lateral rectangular surfaces. Now instead of 3 lateral triangular surfaces, we have 2.

So the total area found previously will be decreased by al

5. so the area now is √3/2a^2 + 2al

6. now a=25 and l=2a=50

Area= √3/2a^2+2al=√3/2*25^2+2*25*50=25^2(√3/2+4)=625*4.866

=3041.3 (ft squared)